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aceburn

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  1. Dry coal C - 75% H - 5% O - 8% Ash - 12 % Basis : 1 Kg coal Coal analysis Components wt% Kg M.W kmol C 75 0.75 12 0.0625 H 5 0.05 1 0.05 O 8 0.08 16 0.005 Ash 12 0.12 - - Total 100 1 The reactions are 30% excess air is used O2 required = 0.0625 + 0.05(0.25) -(0.005/2) = 0.0725 kmol O2 supplied = 0.0725 (1.3) = 0.09425 kmol Air supplied = (0.09425/0.21) = 0.448809 kmol Orsat analysis Components kmol mol% CO2 0.0625 14.24 O2 0.09425 -(0.0725) = 0.02175 4.956 N2 0.448809(0.79) = 0.354559 80.803 Total 0.438809 100 C) For 1 Kg coal dry flue gas = 0.438809(1000) = 438.809 moles For 100 moles of dry gas , coal supplied = 0.22788 Kg D) Refuse obtained for 438.809 moles dry flue gas = 0.12 Kg For 100 moles dry flue gas Refuse obtained = 0.027346 Kg
  2. nagana kaya to try ko nga
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