Klang Posted December 2, 2021 Share Posted December 2, 2021 Chegg unlock This is the hidden content, please Sign In or Sign Up Link to comment Share on other sites More sharing options...
aceburn Posted December 3, 2021 Share Posted December 3, 2021 Dry coal C - 75% H - 5% O - 8% Ash - 12 % Basis : 1 Kg coal Coal analysis Components wt% Kg M.W kmol C 75 0.75 12 0.0625 H 5 0.05 1 0.05 O 8 0.08 16 0.005 Ash 12 0.12 - - Total 100 1 The reactions are 30% excess air is used O2 required = 0.0625 + 0.05(0.25) -(0.005/2) = 0.0725 kmol O2 supplied = 0.0725 (1.3) = 0.09425 kmol Air supplied = (0.09425/0.21) = 0.448809 kmol Orsat analysis Components kmol mol% CO2 0.0625 14.24 O2 0.09425 -(0.0725) = 0.02175 4.956 N2 0.448809(0.79) = 0.354559 80.803 Total 0.438809 100 C) For 1 Kg coal dry flue gas = 0.438809(1000) = 438.809 moles For 100 moles of dry gas , coal supplied = 0.22788 Kg D) Refuse obtained for 438.809 moles dry flue gas = 0.12 Kg For 100 moles dry flue gas Refuse obtained = 0.027346 Kg Link to comment Share on other sites More sharing options...
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