Help to solve Math problem

[KartikIsCrazy]

 

Please give solution done by you didn't online solution beacause it bit tricky and i need simple method

Edited July 29, 2020 by KartikIsCrazy

[Arturo]

Let total no.of deer = x
half of herd =x/2
3/4 of remaining half herd =(x/2)(3/4)
                                          =3x/8
remaining deer=9
x=(x/2)+(3x/8)+9
x=(4x+3x+72)/8
8x=7x+72
8x-7x=72
x=72
∴total no.of deers are 72.

Crdts to brainly

 

It's a site for students where yoi can find answers for diff problems

 

I can say it's  legit coz i use it for my homework

Edited July 29, 2020 by JamesNieto
Removal of unnecessary

[KartikIsCrazy]

9 minutes ago, JamesNieto said:

Let total no.of deer = x
half of herd =x/2
3/4 of remaining half herd =(x/2)(3/4)
                                          =3x/8
remaining deer=9
x=(x/2)+(3x/8)+9
x=(4x+3x+72)/8
8x=7x+72
8x-7x=72
x=72
∴total no.of deers are 72.

Crdts to brainly

 

It's a site for students where yoi can find answers for diff problems

 

I can say it's  legit coz i use it for my homework

Bro need simple method

[Arturo]

Am sorry my bad

[Tzuyu]

9x4x2=72

[Zyy]

What grade are you? You can easily answer those problem if you know how to put it into mathematical equation

[Zyy]

300 total

1 2 and 5

Number of 2 coins is 3times the number of 5 coins total number of coins is 160

 

Okay lets begin

Let x = number of 1 coins

Y= 2 coin

Z= 5coin

 

Number of 2 coin is 3times the number of 5coins means

y=3z

 

Total number of coins is 160 means

x+y+z=160

 

Then total amount is 300 means

X+2y+5z=300

 

Solve simultaneously

 

substitute 

Y=3z to x+y+z=160 and x+2y+5z=300

so, x+3z+z=160 and x+2(3z)+5z=300

Simplify

x+4z=160 and x+11z=300

Solve simultaneously

 

x=160-4z

160-4z+11z=300

7z=300-160

7z=140

z=20

y=3z so y=60

and x+y+z=160 

so x=160-y-z

x=160-20-60

x=80

 

This is just a simple solution if you try to understand it

Edited July 29, 2020 by Zyy

[K4anubhav]

still studying in lockdown