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aceburn

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Posts posted by aceburn

    Help chegg unlock

    in Homework Help

    Posted

    Dry coal

    C - 75%

    H - 5%

    O - 8%

    Ash - 12 %

    Basis : 1 Kg coal

    Coal analysis

    Components wt% Kg M.W kmol
    C 75 0.75 12 0.0625
    H 5 0.05 1 0.05
    O 8 0.08 16 0.005
    Ash 12 0.12 - -
    Total 100 1    

    The reactions are

    C + O_{2}\rightarrow CO_{2}

    2H +-02 + H2O 2

    30% excess air is used

    O2 required = 0.0625 + 0.05(0.25) -(0.005/2) = 0.0725 kmol

    O2 supplied = 0.0725 (1.3) = 0.09425 kmol

    Air supplied = (0.09425/0.21) = 0.448809 kmol

    Orsat analysis

    Components kmol mol%
    CO2 0.0625 14.24
    O2 0.09425 -(0.0725) = 0.02175 4.956
    N2 0.448809(0.79) = 0.354559 80.803
    Total 0.438809 100

    C)

    For 1 Kg coal dry flue gas = 0.438809(1000) = 438.809 moles

    For 100 moles of dry gas , coal supplied = 0.22788 Kg

    D)

    Refuse obtained for 438.809 moles dry flue gas = 0.12 Kg

    For 100 moles dry flue gas

    Refuse obtained = 0.027346 Kg

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