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(COMPLETED) GAME QUIZ #29 : win ×1 Netflix Solo Account + 20 Pesos Load (PRE CALCULUS) "Collaboration"


KING

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   GAMQUIZ

RULES & REQUIREMENTS :

 

1. No double answer ❌

2. Do not edit your answer❌

3. This is only for those who don't have Netflix Solo Account✅

4. Be specific ✅

5. Wrong spelling is WRONG ✅

6. Whoever answer first is the WINNER?

7. React to this topic ❤️

 

COLLABORATION w/@D4rk_c0d3r❤️

Screenshot_20200808_164604.jpg.08850c730023f054f4b4d2dd27dee7ab.jpg

 

GAME? Let's start! 

Spoiler

This is the hidden content, please

1239711010_giphy(1).gif.b09fc08da8ad12c3985b694299bfb8fd.gif

Edited by KING
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3 minutes ago, jaoster said:

thanks lods

 

7 minutes ago, Anubis said:

Thanks for sharing 

 

8 minutes ago, Tzuyu said:

thanks for sharing po boss

 

17 minutes ago, Bea said:

Thanks for sharing

 

18 minutes ago, Yatchi said:

Thanks for sharing.

 

 

18 minutes ago, Lokesh said:

Thanks for sharing

WELCOME ❤️

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6 minutes ago, Lokesh said:

Is it rightIMG20200808144141.thumb.jpg.ec1ae00ccbf09840189bec469b681c13.jpg

 

3 minutes ago, banana_que said:

Equation. Center. Transverse Axis. Vertices.

3E57DD5D-2994-4C72-8D65-10568CE1D793.jpeg

 

3 minutes ago, Vishalrathee said:

Y=k+(x-h)

Y=k-(x-h)

IMG_20200808_150204.jpg

INCOMPLETE ANSWER ❤️

 

Give the equation and the example (Picture).✅

Edited by KING
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Just now, Miks said:

A32F4FC1-51E1-48AF-96E4-CCC03F15D212.jpeg

INCOMPLETE ANSWER ❤️

 

Give the equation and example of it in Paragraph form❤️

Just now, Vishalrathee said:

A hyperbola with avertical transverse axisand center at (h, k) has one asymptote withequation y = k + (x - h) and the other with equation y = k - (x -h).

INCORRECT ❌

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1 minute ago, banana_que said:

he standard equation for a hyperbola with a horizontal transverse axis is 

This is the hidden content, please
 - 
This is the hidden content, please
 = 1. The center is at (h, k). The distance between the vertices is 2a. The distance between the foci is 2c.  c2 = a2 + b2. The line segment of length 2bperpendicular to the transverse axis whose midpoint is the center is the conjugate axis of the hyperbola.

EF200CEF-BB63-41D2-8F83-477ABBF56E54.jpeg

Naunahan ka lods Sayang❤️

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